Решить систему уравнений по формулам Крамера

x-2y+3z=6 2x+3y-4z=20 3x-2y+5z=6

x - 2y + 3z = 6

2x + 3y - 4z = 20

3x - 2y + 5z = 6

∆ = 1 - 2 3 = 12

2 3 - 4

3 - 2 5

∆1 = 6 - 2 3 = 116

20 3 - 4

6 - 2 5

∆2 = 1 6 3 = - 152

2 20 - 4

3 6 5

∆3 = 1 - 2 6 = - 116

2 3 20

3 - 2 6

x1 = ∆1 / ∆ = 116 / 12 = 29/3

x2 = ∆2 / ∆ = - 152 / 12 = - 38 / 3

x3 = ∆3 / ∆ = - 116 / 12 = - 29 / 3