Sin (-7 п) - tg (7 п/3) - корень из 3 cos (-7 П/4)

Sin (-7π) - tg (7π/3) - √3cos (-7π/4) = - sin (7π) - tg (7π/3) - √3cos (7π/4) =

=-sin (π+6π) - tg (π/3+2π) - √3cos (3π/4+π) =

=0-tg (π/3) + √3cos (3π/4) = - √3+√3·cos (π-π/4) = - √3-√3·√2/2=

=-√3 (1+√2/2);