Решить уравнение:sint/1-cost=0

a) sin (t) * 2cos (t) + 1) = 0

1) sin (t) = 0

t=pi*n

2) 2*cos (t) + 1=0

2*cos (t) = - 1

cos (t) = - 1/2

t=±arccos (-1/2) + 2*pi/n

t=± (4*pi/3) + 2*pi*n

б) (sin (t) - 1) * (cos (t) + 1) = 0

1) sin (t) - 1=0

sin (t) = 1

t = (pi/2) + 2*pi*n

2) cos (t) + 1=0

cos (t) = - 1

t=pi+2*pi*n

в) cos (t) * (2sin (t) + 1) = 0

1) cos (t) = 0

t = (pi/2) + pi*n

2) 2*sin (t) + 1=0

2*sin (t) = - 1

sin (t) = - 1/2

t = (-1) ^n*arcsin (-1/2) + pi*n

t = (7*pi/6) + pi*n

г) 2sin (t) - sqrt (2)) * (2*cos (t) + 1) = 0

1) 2*sin (t) - sqrt (2) = 0

2*sin (t) = sqrt (2)

sin (t) = sqrt (2) / 2

t = (pi/4) + pi*n

2) 2*cos (t) + 1=0

2*cos (t) = - 1

cos (t) = - 1/2

t = ±arccos (-1/2) + 2*pi*n

t=± (4*pi/3) + 2*pi*n