Решите уравнение Sin 4x/Cos 2x=2 Sin x

Sin4x/cos2x = 2sinx

2sin2x*cos2x / cos2x = 2sinx

2sin2x - 2 sinx = 0

2sinxcosx - sinx = 0

sinx (2cosx - 1) = 0

1) sinx = 0

x1 = πn, n∈Z

2) 2cosx - 1 = 0

cosx = 1/2

x = ( + - ) arccos (1/2) + 2πk, k∈Z

x2 = ( + - ) * (π/3) + 2πk, k∈Z