Решить уравнение:

(х²-3 х+2) (х²-4 х+3) = 0

Решение:

(x^2-3x+2) (x^2-4x+3) = 0

x^2-3x+2=0

x1,2 = (3+-D) / 2*1

D=√ (9-4*1*2) = √ (9-8) = √1=1

x1,2 = (3+-1) / 2

x1 = (3+1) / 2

x1=2

x2 = (3-1) / 2

x2=1

x^2-4x+3=0

x3,4 = (4+-D) / 2*1

D=√ (16-4*1*3) = √ (16-12) = √4=2

x3,4 = (4+-2) / 2

x3 = (4+2) / 2

x3=3

x4 = (4-2) / 2

x4=1

Ответ: (1; 2; 3)

(х²-3 х+2) (х²-4 х+3) = 0

x ²-3x+2=0 х²-4 х+3=0

D=9-4*2=1 D=16-4*3=4

x1 = (3+1) / 2=2 √D=2

x2 = (3-1) / 2=1 x1 = (4+2) / 2=3

x2 = (4-2) / 2=1