Помогите решить уравнение:

4,2-0,2: (1/6+3b) = 3 3/5

4,2-0,2: (1/6+3b) = 3 3/5

- 0,2: (1/6 + 3b) = 3,6 - 4,2

-0,2: (1/6+3b) = - 0,6

-0,2: (-0,6) = 1/6+3b

-2/10 : - 6/10 = 1/6 + 3b

2/10• 10/6 = 1/6 + 3b

2/1• 1/6 = 1/6+3b

2/6 - 1/6 = 3b

1/6 = 3b

b = 1/6: 3

b = 1/6• 1/3

b = 1/18

4,2-0,2: (1/6+3b) = 3 3/5

4,2-0,2: (1/6 + 3•1/18) = 3 3/5

4,2 - 0,2: (1/6 + 1• 1/6) = 3 3/5

4,2 - 2/10: 2/6 = 3 3/5

42/10 - 2/10• 6/2 = 3 3/5

42/10 - 1/10• 6/1 = 3 3/5

42/10 - 6/10 = 3 3/5

36/10 = 3 3/5

3 6/10 = 3 3/5

3 3/5 = 3 3/5