F' (x) = (2/3) x^ (-1/3)

f' (8) = (2/3) * 8^ (-1/3) = (2/3) * (1/2) = 1/3

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Математика

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30 июня, 11:46

F' (x) = (2/3) x^ (-1/3)

f' (8) = (2/3) * 8^ (-1/3) = (2/3) * (1/2) = 1/3

+4

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Натан · Answer 1

у меня 2 варианта:

1) если ваша функция равна f (x) = x^ (2/3) + 5, то

f' (x) = (2/3) x^ (-1/3)

f' (8) = (2/3) * 8^ (-1/3) = (2/3) * (1/2) = 1/3

2) если ваша функция равна f (x) = (x^2) / 3 + 5, то

f' (x) = 2x/3

f' (8) = 2*8/3 = 16/3

F' (x) = (2/3) x^ (-1/3)f' (8) = (2/3) * 8^ (-1/3) = (2/3) * (1/2) = 1/3

F' (x) = (2/3) x^ (-1/3)

f' (8) = (2/3) * 8^ (-1/3) = (2/3) * (1/2) = 1/3