Sin^2 (2x) - cos (4x) - 2 = 0 решить уравнение

Замена 2x=t

sin²t-cos (2t) - 2=0

sin²t - (cos²t-sin²t) - 2=0

sin²t-cos²t+sin²t-2=0

2sin²t-cos²t-2=0

cos²t=1-sin²t

2sin²t - (1-sin²t) - 2=0

2sin²t-1+sin²t-2=0

3sin²t=3

sin²t=1

sint=±1

t=±P/2 + pn

2x=±p/2+pn

x=±p/4+pn/2 n € z, z-целое