Решить одно уравнение

Х+1+√ (х+1) = 6

√ (x + 1) = 6 - x - 1

√ (x + 1) = 5 - x

x + 1 = (5 - x) ²

x + 1 = (5 - x) (5 - x)

x + 1 = 25 - 10x + x²

- x² + 11x - 24 = 0

x² - 11x + 24 = 0

D = b² - 4ac = 121 - 4 * 24 = 121 - 96 = 25 = 5²

x1 = (11 + 5) / 2 = 8

x2 = (11 - 5) / 2 = 3