Log 3 32 • log2 25 • log 0.2 3

Log₃32*log₂25*log₀,₂3=-10

переход к новому основанию 2.

1. log₃32=log₃2⁵=5*log₃2=5 * (log₂2/log₂3) = 5 * (1/log₂3) = 5/log₂3

2. log₂25=log₂5²=2*log₂5

3. log₀,₂3=log₁/₅5=log₂3/log₂ (1/5) = log₂3 / (log₂5⁻¹) = - log₂3/log₂5

4. (5/log₂3) * (2*log₂5) * (-log₂3/log₂5) = 5*2 * (-1) = - 10