Решить неравенство:

log2 (x^2 - 3x + 2) ≤ 1 + log2 (x-2)

ОДЗ

x > 2

log2 (x^2 - 3x + 2) ≤ log2 (2) + log2 (x - 2)

log2 (x^2 - 3x + 2) ≤ log2 (2x - 4)

x^2 - 3x + 2 ≤ 2x - 4

x^2 - 5x + 6 ≤ 0

x^2 - 5x + 6 = 0

D = 25 - 24 = 1

x1 = (5 + 1) / 2 = 3

x2 = (5 - 1) / 2 = 2

(x - 3) (x - 2) ≤ 0

x ∈ [ 2; 3]

+ ОДЗ

x ∈ (2; 3]