Log по основанию 1/9 (13-х) = - 2

log по основанию 4 (х^2+х) = log 4 (х^2+6)

log по основанию 2 (8+3 х) = log 2 (3+x) + 1

1) log 1/9 (13-x) = - 2

-log 9 (13-x) = - 2 ] * (-1)

log 9 (13-x) = 2

2log 3 (13-x) = 2 ]:2

log3 (13-x) = 1

log3 (13-x) = log3 (3)

13-x=3

x=13-3

x=10

2) log 4 (х^2+х) = log 4 (х^2+6)

х^2+х=х^2+6

x=6

3) log 2 (8+3 х) = log 2 (3+x) + 1

log2 (8+3 х) = log 2 (3+x) + log2 (2)

log2 (8+3 х) = log 2 (2 * (3+x))

8+3x=6+2x

3x-2x=6-8

x=-2