Приведите уравнение к виду ax^2+bx+c=0

1) x (3x+5) - 1=x (x-4)

2) (6+x) ^2 = (x-2) (3-x)

3) (7x-1) (2+x) = (x-4) (x+4)

3) x (8-3x) = (5x-1) ^2

1) x (3x+5) - 1=x (x-4)

3x^2+5x-1=x^2-4x

2x^2+9x-1=0

2) (6+x) ^2 = (x-2) (3-x)

36+12x+x^2 = 3x-x^2-6+2x

2x^2+7x+42=0

3) (7x-1) (2+x) = (x-4) (x+4)

14x+7x^2-2-x = x^2+4x-4x-16

6x^2+13x+14=0

3) x (8-3x) = (5x-1) ^2

8x-3x^2=25x^2-10x+1

28x^2-18x+1=0