Решите уравнение: б) (x^2-3) (x+2) + (x^2+3) (x-2) = 4

в) (x-4) (x+3) + (x-2) (x+3) = 0

г) (x^2-1) (x-4) + (x^2+1) (x+4) = 6

(x^2-3) (x+2) + (x^2+3) (x-2) = 4

2 (x^3-6) = 4

2x^3-12=4

2x^3-16=0

x^3-8=0

x^3=2^3

x=2

(x-4) (x+3) + (x-2) (x+3)

(x-4+x-2) (x+3)

(2x-6) (x+3) = 0

x=3 x=-3

(x^2-1) (x-4) + (x^2+1) (x+4) = 6

2 (x^3+4) = 6

2x^3+8=6

2x^3+2=0

x^3+1=0

x^3=-1^3

x=-1