Sin ((3π) / 2 - 2π) + 5sin (π-x) + 3=0

Решение

Sin ((3π) / 2 - 2π) + 5sin (π-x) + 3=0

Sin (( - π/2) + 5sin (π-x) + 3=0

- 1 + 5sinx + 3 = 0

sinx = - 2/5

x = ( - 1) ^n*arcsin ( - 2/5) + πn, n ∈ Z

x = ( - 1) ^ (n+1) * arcsin (2/5) + πn, n ∈ Z